6) \( tg 45° \cdot cos 60° = 1 \cdot \frac{1}{2} = \frac{1}{2} \)
в) \( \frac{tg 30°}{sin 45°} = \frac{\frac{\sqrt{3}}{3}}{\frac{\sqrt{2}}{2}} = \frac{\sqrt{3}}{3} \cdot \frac{2}{\sqrt{2}} = \frac{2\sqrt{3}}{3\sqrt{2}} = \frac{2\sqrt{3}\sqrt{2}}{3\cdot 2} = \frac{\sqrt{6}}{3} \)
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