Решение:
1. \[(\frac{1}{9})^2 = \frac{1}{9} \cdot \frac{1}{9} = \frac{1}{81}\]
2. \[18 \cdot \frac{1}{81} = \frac{18}{81} = \frac{2}{9}\]
3. \[20 \cdot \frac{1}{9} = \frac{20}{9}\]
4. \[\frac{2}{9} - \frac{20}{9} = \frac{2 - 20}{9} = \frac{-18}{9} = -2\]
Ответ: -2