Вычислите: $(15-9\frac{2}{3}):\frac{2}{3}:(19\frac{2}{3}-11\frac{7}{9}):\frac{9}{71}$

Решим пошагово: 1. $15-9\frac{2}{3} = 15 - \frac{29}{3} = \frac{45}{3} - \frac{29}{3} = \frac{16}{3}$ 2. $\frac{16}{3} : \frac{2}{3} = \frac{16}{3} \times \frac{3}{2} = \frac{16}{2} = 8$ 3. $19\frac{2}{3} - 11\frac{7}{9} = \frac{59}{3} - \frac{106}{9} = \frac{177}{9} - \frac{106}{9} = \frac{71}{9}$ 4. $8 : \frac{71}{9} = 8 \times \frac{9}{71} = \frac{72}{71}$ 5. $\frac{72}{71} : \frac{9}{71} = \frac{72}{71} \times \frac{71}{9} = \frac{72}{9} = 8$ Ответ: 8