Решение:
\((2x+5)(x-6)+2(3x+2)(3x-2) = 5(2x+1)^2 + 11\)
\(2x^2 -12x + 5x -30 + 2(9x^2 - 4) = 5(4x^2 + 4x + 1) + 11\)
\(2x^2 -7x -30 + 18x^2 - 8 = 20x^2 + 20x + 5 + 11\)
\(20x^2 -7x -38 = 20x^2 + 20x + 16\)
\(-7x - 20x = 16 + 38\)
\(-27x = 54\)
\(x = -2\)
Ответ: x = -2