4. Найдите значение выражений: 1) \(3\frac{3}{8} : \frac{1}{2} - 1 \frac{1}{7} \cdot 7\) 2) \(3 : 3\frac{3}{4} + 2\frac{1}{2} \cdot 2 - 3\frac{5}{6}\) 3) \((4\frac{5}{12} + 1 \frac{1}{4}) : (6\frac{2}{15} - 1 \frac{1}{5})\) 4) \(2 \frac{2}{3} \cdot (2\frac{1}{2} + 2\frac{2}{15}) - 8 \frac{4}{5}\) 5) \((5 \frac{3}{7} \cdot 5 - 5 \frac{1}{4} : 7) : 3 + 3 \frac{3}{28} - 2 \frac{1}{2}\)

1) \(3\frac{3}{8} : \frac{1}{2} - 1 \frac{1}{7} \cdot 7 = \frac{27}{8} : \frac{1}{2} - \frac{8}{7} \cdot 7 = \frac{27}{8} \cdot 2 - 8 = \frac{27}{4} - 8 = \frac{27 - 32}{4} = -\frac{5}{4} = -1\frac{1}{4}\) 2) \(3 : 3\frac{3}{4} + 2\frac{1}{2} \cdot 2 - 3\frac{5}{6} = 3 : \frac{15}{4} + \frac{5}{2} \cdot 2 - \frac{23}{6} = 3 \cdot \frac{4}{15} + 5 - \frac{23}{6} = \frac{4}{5} + 5 - \frac{23}{6} = \frac{24 + 150 - 115}{30} = \frac{59}{30} = 1\frac{29}{30}\) 3) \((4\frac{5}{12} + 1 \frac{1}{4}) : (6\frac{2}{15} - 1 \frac{1}{5}) = (\frac{53}{12} + \frac{5}{4}) : (\frac{92}{15} - \frac{6}{5}) = (\frac{53 + 15}{12}) : (\frac{92 - 18}{15}) = \frac{68}{12} : \frac{74}{15} = \frac{17}{3} : \frac{74}{15} = \frac{17}{3} \cdot \frac{15}{74} = \frac{17 \cdot 5}{74} = \frac{85}{74} = 1\frac{11}{74}\) 4) \(2 \frac{2}{3} \cdot (2\frac{1}{2} + 2\frac{2}{15}) - 8 \frac{4}{5} = \frac{8}{3} \cdot (\frac{5}{2} + \frac{32}{15}) - \frac{44}{5} = \frac{8}{3} \cdot (\frac{75 + 64}{30}) - \frac{44}{5} = \frac{8}{3} \cdot \frac{139}{30} - \frac{44}{5} = \frac{4 \cdot 139}{3 \cdot 15} - \frac{44}{5} = \frac{556}{45} - \frac{44}{5} = \frac{556 - 44 \cdot 9}{45} = \frac{556 - 396}{45} = \frac{160}{45} = \frac{32}{9} = 3\frac{5}{9}\) 5) \((5 \frac{3}{7} \cdot 5 - 5 \frac{1}{4} : 7) : 3 + 3 \frac{3}{28} - 2 \frac{1}{2} = (\frac{38}{7} \cdot 5 - \frac{21}{4} : 7) : 3 + \frac{87}{28} - \frac{5}{2} = (\frac{190}{7} - \frac{21}{4 \cdot 7}) : 3 + \frac{87}{28} - \frac{5}{2} = (\frac{190}{7} - \frac{3}{4}) : 3 + \frac{87}{28} - \frac{5}{2} = (\frac{190 \cdot 4 - 3 \cdot 7}{28}) : 3 + \frac{87}{28} - \frac{5}{2} = \frac{760 - 21}{28} : 3 + \frac{87}{28} - \frac{5}{2} = \frac{739}{28} : 3 + \frac{87}{28} - \frac{5}{2} = \frac{739}{28 \cdot 3} + \frac{87}{28} - \frac{5}{2} = \frac{739}{84} + \frac{87}{28} - \frac{5}{2} = \frac{739 + 87 \cdot 3 - 5 \cdot 42}{84} = \frac{739 + 261 - 210}{84} = \frac{790}{84} = \frac{395}{42} = 9\frac{17}{42}\)