Решение:
1. \(2\frac{2}{3} = \frac{2 \cdot 3 + 2}{3} = \frac{8}{3}\)
2. \(1\frac{4}{5} = \frac{1 \cdot 5 + 4}{5} = \frac{9}{5}\)
3. \(3\frac{1}{3} = \frac{3 \cdot 3 + 1}{3} = \frac{10}{3}\)
4. \(2 : \frac{8}{3} = 2 \cdot \frac{3}{8} = \frac{6}{8} = \frac{3}{4}\)
5. \(\frac{9}{5} \cdot \frac{10}{3} = \frac{9 \cdot 10}{5 \cdot 3} = \frac{90}{15} = 6\)
6. \(2\frac{5}{6} = \frac{2 \cdot 6 + 5}{6} = \frac{17}{6}\)
7. \(\frac{3}{4} + 6 - \frac{17}{6} = \frac{3}{4} + \frac{24}{4} - \frac{17}{6} = \frac{27}{4} - \frac{17}{6} = \frac{27 \cdot 3 - 17 \cdot 2}{12} = \frac{81 - 34}{12} = \frac{47}{12} = 3\frac{11}{12}\)
Ответ: \(3\frac{11}{12}\)
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