Вариант 1. 13. (1 - log_2(12)) * (1 - log_6(12))

1 - log_2(12) = log_2(2) - log_2(12) = log_2(2/12) = log_2(1/6). 1 - log_6(12) = log_6(6) - log_6(12) = log_6(6/12) = log_6(1/2). Тогда (1 - log_2(12)) * (1 - log_6(12)) = log_2(1/6) * log_6(1/2) = log_2(6^(-1)) * log_6(2^(-1)) = (-1*log_2(6)) * (-1*log_6(2)). = log_2(6) * log_6(2) = log_2(2) = 1 Ответ: 1