$\vec{AB} = (1-3; \frac{5}{6}-(-2); \frac{6}{3}-3) = (-2; \frac{17}{6}; -1)$
$\vec{BC} = (\frac{1}{2}-1; \frac{1}{3}-\frac{5}{6}; \frac{1}{4}-\frac{6}{3}) = (-\frac{1}{2}; -\frac{3}{6}; -\frac{21}{12}) = (-\frac{1}{2}; -\frac{1}{2}; -\frac{7}{4})$
$\vec{AC} = (\frac{1}{2}-3; \frac{1}{3}-(-2); \frac{1}{4}-3) = (-\frac{5}{2}; \frac{7}{3}; -\frac{11}{4})$
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