$\frac{3}{\pi} (arcsin(-\frac{\sqrt{3}}{2}) + arctg 1)$
$arcsin(-\frac{\sqrt{3}}{2}) = -\frac{\pi}{3}$
$arctg 1 = \frac{\pi}{4}$
$\frac{3}{\pi} (-\frac{\pi}{3} + \frac{\pi}{4}) = \frac{3}{\pi} (\frac{-\pi}{12}) = -\frac{3\pi}{12\pi} = -\frac{1}{4}$
Ответ: -$\frac{1}{4}$
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