Решите выражение (e): 12\frac{3}{7} : 4\frac{5}{6} + 48\frac{3}{5} : 6\frac{3}{4}

1. (12\frac{3}{7} = \frac{87}{7}\) 2. (4\frac{5}{6} = \frac{29}{6}\) 3. (48\frac{3}{5} = \frac{243}{5}\) 4. (6\frac{3}{4} = \frac{27}{4}\) 5. \(\frac{87}{7} : \frac{29}{6} = \frac{87}{7} \cdot \frac{6}{29} = \frac{3}{7} \cdot 6 = \frac{18}{7}\) 6. \(\frac{243}{5} : \frac{27}{4} = \frac{243}{5} \cdot \frac{4}{27} = \frac{9}{5} \cdot 4 = \frac{36}{5}\) 7. \(\frac{18}{7} + \frac{36}{5}\) Общий знаменатель 35. \(\frac{18}{7} = \frac{90}{35}\) и \(\frac{36}{5} = \frac{252}{35}\) 8. \(\frac{90}{35} + \frac{252}{35} = \frac{342}{35} = 9\frac{27}{35}\) Ответ: (9\frac{27}{35}\)