Решите выражение (б): 4\frac{3}{4} : \frac{3}{5} : 2\frac{11}{42} - \frac{1}{2}

1. \(4\frac{3}{4} = \frac{19}{4}\) 2. \(2\frac{11}{42} = \frac{95}{42}\) 3. \(\frac{19}{4} : \frac{3}{5} = \frac{19}{4} \cdot \frac{5}{3} = \frac{95}{12}\) 4. \(\frac{95}{12} : \frac{95}{42} = \frac{95}{12} \cdot \frac{42}{95} = \frac{42}{12} = \frac{7}{2}\) 5. \(\frac{7}{2} - \frac{1}{2} = \frac{6}{2} = 3\) Ответ: 3