Решите уравнение: 25x^3-10x^2+x=0.

\[25x^{3} - 10x^{2} + x = 0\]

\[x \cdot (5x - 1)^{2} = 0\]

\[x = 0\ \ \ \ \ \ \ \ \ \ \ 5x - 1 = 0\ \]

\[\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5x = 1\]

\[\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = \frac{1}{5} = 0,2\]

\[Ответ:x = 0;\ \ x = 0,2.\]