Решите уравнение: x^3-5x^2+9x-45=0.

\[x^{3} - 5x^{2} + 9x - 45 = 0\]

\[x^{2} \cdot (x - 5) + 9 \cdot (x - 5) = 0\]

\[(x - 5)\left( x^{2} + 9 \right) = 0\]

\[x - 5 = 0\ \ \ \ \ \ \ \ \ \ \ \ \ x^{2} + 9 = 0\]

\[Ответ:x = 5.\]