Решите уравнение: x^3+3x^2-4x-12=0.

\[x^{3} + 3x^{2} - 4x - 12 = 0\]

\[x^{2} \cdot (x + 3) - 4 \cdot (x + 3) = 0\]

\[(x + 3)\left( x^{2} - 4 \right) = 0\]

\[(x + 3)(x - 2)(x + 2) = 0\]

\[x = - 3;\ \ \ \ x = 2;\ \ \ \ \ x = - 2\]

\[Ответ:x = - 3;\ x = \pm 2.\]