Решите уравнение: 6x^3-24x=0.

\[6x^{3} - 24x = 0\]

\[6x \cdot \left( x^{2} - 4 \right) = 0\]

\[6x \cdot (x - 2)(x + 2) = 0\]

\[x = 0;\ \ \ \ \ x = 2;\ \ \ \ x = - 2\]

\[Ответ:x = 0;\ x = \pm 2.\]