Решите неравенство: 25/(2x+3)^2 -30/(2x+3)-7<=0.

\[\frac{7x^{2} + 36x + 32}{(2x + 3)^{2}} \geq 0\]

\[\frac{7 \cdot (x + 4)\left( x + 1\frac{1}{7} \right)}{4 \cdot (x + 1,5)^{2}} \geq 0\]

\[Ответ:\ \ ( - \infty; - 4\rbrack \cup \left\lbrack - 1\frac{1}{7};\ + \infty \right).\]