\[3,\ b_{n},\ 2\frac{1}{2},\ b_{n} = \frac{4^{n + 2}}{5},\ \ldots\]
\[b_{1} = \frac{4^{3}}{5} = \frac{64}{5};\ b_{3} = 2\frac{1}{2};\ \]
\[b_{2} = \frac{b_{1} + b_{3}}{2} = \frac{3 + 2,5}{2} =\]
\[= \frac{5,5}{2} = \frac{11}{4} = 2\frac{3}{4};\]
\[b_{2} = \frac{4^{4}}{5} = \frac{256}{5} = 51\frac{1}{5}.\]
\[b_{2}
eq b_{2}\]
\[Дана\ неверная\ \]
\[последовательность.\]