Решебник по математике 6 класс Мерзляк ФГОС Задание 270

 

\[\boxed{\mathbf{270\ (269)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \frac{1^{\backslash 5}}{4} + \frac{3^{\backslash 4}}{5} = \frac{5 + 12}{20} = \frac{17}{20}\]

\[2)\ \frac{9^{\backslash 5}}{11} - \frac{2^{\backslash 11}}{5} = \frac{45 - 22}{55} = \frac{23}{55}\]

\[3)\ \frac{13^{\backslash 2}}{16} - \frac{9}{32} = \frac{26 - 9}{32} = \frac{17}{32}\]

\[4)\ \frac{3}{28} + \frac{5^{\backslash 2}}{14} = \frac{3 + 10}{28} = \frac{13}{28}\]

\[5)\ \frac{14^{\backslash 2}}{15} - \frac{7^{\backslash 3}}{10} = \frac{28 - 21}{30} = \frac{7}{30}\]

\[6)\ \frac{3^{\backslash 3}}{8} + \frac{1^{\backslash 4}}{6} = \frac{9 + 4}{24} = \frac{13}{24}\]

\[7)\ \frac{9^{\backslash 4}}{25} - \frac{7^{\backslash 5}}{20} = \frac{36 - 35}{100} = \frac{1}{100}\]

\[8)\ \frac{37^{\backslash 4}}{42} - \frac{17^{\backslash 7}}{24} = \frac{148 - 119}{168} =\]

\[= \frac{29}{168}\]

\[9)\ \frac{11^{\backslash 2}}{24} - \frac{3^{\backslash 3}}{16} = \frac{22 - 9}{48} = \frac{13}{48}\]

\[10)\ \frac{9^{\backslash 3}}{16} + \frac{7^{\backslash 2}}{24} - \frac{3^{\backslash 6}}{8} =\]

\[= \frac{27 + 14 - 18}{48} = \frac{23}{48}\]

\[11)\ \frac{1^{\backslash 4}}{3} - \frac{1^{\backslash 2}}{6} + \frac{1^{\backslash 3}}{4} =\]

\[= \frac{4 - 2 + 3}{12} = \frac{5}{12}\]

\[12)\ \frac{2^{\backslash 9}}{5} + \frac{4^{\backslash 3}}{15} - \frac{5^{\backslash 5}}{9} =\]

\[= \frac{18 + 12 - 25}{45} = \frac{5}{45} = \frac{1}{9}\]

\[\boxed{\mathbf{270\ (}\mathbf{с}\mathbf{)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \frac{25}{80} + \frac{45}{60} = \frac{5}{16} + \frac{3^{\backslash 4}}{4} =\]

\[= \frac{5 + 12}{16} = \frac{17}{16} = 1\frac{1}{16}\]

\[2)\ \frac{20}{45} + \frac{26}{54} = \frac{4^{\backslash 3}}{9} + \frac{13}{27} =\]

\[= \frac{12 + 13}{27} = \frac{25}{27}\]

\[3)\ \frac{36}{300} + \frac{12}{40} - \frac{350}{1000} =\]

\[= \frac{3^{\backslash 4}}{25} + \frac{3^{\backslash 10}}{10} - \frac{7^{\backslash 5}}{20} =\]

\[= \frac{12 + 30 - 35}{100} = \frac{7}{100}\]

\[4)\ \frac{14}{24} - \frac{39}{90} + \frac{15}{100} =\]

\[= \frac{7^{\backslash 5}}{12} - \frac{13^{\backslash 2}}{30} + \frac{3^{\backslash 3}}{20} =\]

\[= \frac{35 - 26 + 9}{60} = \frac{18}{60} = \frac{3}{10}\]

\[5)\ \frac{42}{120} + \frac{20}{32} - \frac{28}{160} =\]

\[= \frac{7^{\backslash 2}}{20} + \frac{5^{\backslash 5}}{8} - \frac{7}{40} =\]

\[= \frac{14 + 25 - 7}{40} = \frac{32}{40} = \frac{4}{5}\]

\[6)\ \frac{45}{72} - \frac{33}{144} - \frac{20}{64} =\]

\[= \frac{5^{\backslash 6}}{8} - \frac{11}{48} - \frac{5^{\backslash 3}}{16} =\]

\[= \frac{30 - 11 - 15}{48} = \frac{4}{48} = \frac{1}{12}\]

\[\boxed{\mathbf{270}\mathbf{.}}\]

\[d = 2r = 2 \cdot 2\ см\ 5\ мм =\]

\[= 4\ см\ 10\ мм = 5\ см.\]