Решебник по математике 6 класс Мерзляк ФГОС Задание 271

 

\[\boxed{\mathbf{271\ (270)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \frac{25}{80} + \frac{45}{60} = \frac{5}{16} + \frac{3^{\backslash 4}}{4} =\]

\[= \frac{5 + 12}{16} = \frac{17}{16} = 1\frac{1}{16}\]

\[2)\ \frac{20}{45} + \frac{26}{54} = \frac{4^{\backslash 3}}{9} + \frac{13}{27} =\]

\[= \frac{12 + 13}{27} = \frac{25}{27}\]

\[3)\ \frac{36}{300} + \frac{12}{40} - \frac{350}{1000} =\]

\[= \frac{3^{\backslash 4}}{25} + \frac{3^{\backslash 10}}{10} - \frac{7^{\backslash 5}}{20} =\]

\[= \frac{12 + 30 - 35}{100} = \frac{7}{100}\]

\[4)\ \frac{14}{24} - \frac{39}{90} + \frac{15}{100} =\]

\[= \frac{7^{\backslash 5}}{12} - \frac{13^{\backslash 2}}{30} + \frac{3^{\backslash 3}}{20} =\]

\[= \frac{35 - 26 + 9}{60} = \frac{18}{60} = \frac{3}{10}\]

\[5)\ \frac{42}{120} + \frac{20}{32} - \frac{28}{160} =\]

\[= \frac{7^{\backslash 2}}{20} + \frac{5^{\backslash 5}}{8} - \frac{7}{40} =\]

\[= \frac{14 + 25 - 7}{40} = \frac{32}{40} = \frac{4}{5}\]

\[6)\ \frac{45}{72} - \frac{33}{144} - \frac{20}{64} =\]

\[= \frac{5^{\backslash 6}}{8} - \frac{11}{48} - \frac{5^{\backslash 3}}{16} =\]

\[= \frac{30 - 11 - 15}{48} = \frac{4}{48} = \frac{1}{12}\]

\[\boxed{\mathbf{271\ (}\mathbf{с}\mathbf{)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[Сравним:\]

\[\frac{3}{10} = \frac{9}{30};\text{\ \ \ }\frac{4}{15} = \frac{8}{30};\ \ \ \frac{3}{10} > \frac{4}{15}.\]

\[\frac{9}{30} - \frac{8}{30} = \frac{1}{30}.\]

\[В\ первой\ банке\ сметаны\]

\[\ больше\ на\ \ \frac{1}{30}\ л.\]

\[Ответ:в\ первой\ банке\ сметаны\ \]

\[больше\ на\ \frac{1}{30}\ л.\]

\[\boxed{\mathbf{271}\mathbf{.}}\]

\[d = 2r = 2 \cdot 3\ см\ 2\ мм =\]

\[= 6\ см\ 4\ мм.\]