Решебник по математике 6 класс Мерзляк ФГОС Задание 269

 

\[\boxed{\mathbf{269\ (268)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \frac{3^{\backslash 9}}{7} + \frac{4^{\backslash 7}}{9} = \frac{27 + 28}{63} = \frac{55}{63}\]

\[2)\ \frac{8^{\backslash 8}}{9} - \frac{7^{\backslash 9}}{8} = \frac{64 - 63}{72} = \frac{1}{72}\]

\[3)\ \frac{13}{15} - \frac{2^{\backslash 5}}{3} = \frac{13 - 10}{15} = \frac{3}{15} =\]

\[= \frac{1}{5}\]

\[4)\ \frac{20}{21} + \frac{3^{\backslash 3}}{7} = \frac{20 + 9}{21} = \frac{29}{21} =\]

\[= 1\frac{8}{21}\]

\[5)\ \frac{17^{\backslash 2}}{18} - \frac{11^{\backslash 3}}{12} = \frac{34 - 33}{36} =\]

\[= \frac{1}{36}\]

\[6)\ \frac{7^{\backslash 3}}{16} + \frac{1^{\backslash 8}}{6} = \frac{21 + 8}{48} = \frac{29}{48}\]

\[7)\ \frac{2^{\backslash 2}}{9} + \frac{5^{\backslash 3}}{6} = \frac{4 + 15}{18} = \frac{19}{18} =\]

\[= 1\frac{1}{18}\]

\[8)\ \frac{10^{\backslash 2}}{21} + \frac{9^{\backslash 3}}{14} = \frac{20 + 27}{42} = \frac{47}{42} =\]

\[= 1\frac{5}{42}\]

\[9)\ \frac{7^{\backslash 5}}{9} - \frac{4^{\backslash 3}}{15} = \frac{35 - 12}{45} = \frac{23}{45}\]

\[10)\ \frac{9^{\backslash 2}}{14} - \frac{3^{\backslash 4}}{7} + \frac{15}{28} =\]

\[= \frac{18 - 12 + 15}{28} = \frac{21}{28} = \frac{3}{4}\]

\[11)\ \frac{1^{\backslash 4}}{6} + \frac{1^{\backslash 6}}{4} - \frac{1^{\backslash 3}}{8} =\]

\[= \frac{4 + 6 - 3}{24} = \frac{7}{24}\]

\[12)\ \frac{13^{\backslash 5}}{18} - \frac{29^{\backslash 2}}{45} + \frac{8^{\backslash 6}}{15} =\]

\[= \frac{65 - 58 + 48}{90} = \frac{55}{90} = \frac{11}{18}\]

\[\boxed{\mathbf{269\ (}\mathbf{с}\mathbf{)}\mathbf{.}\mathbf{\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ \frac{1^{\backslash 5}}{4} + \frac{3^{\backslash 4}}{5} = \frac{5 + 12}{20} = \frac{17}{20}\]

\[2)\ \frac{9^{\backslash 5}}{11} - \frac{2^{\backslash 11}}{5} = \frac{45 - 22}{55} = \frac{23}{55}\]

\[3)\ \frac{13^{\backslash 2}}{16} - \frac{9}{32} = \frac{26 - 9}{32} = \frac{17}{32}\]

\[4)\ \frac{3}{28} + \frac{5^{\backslash 2}}{14} = \frac{3 + 10}{28} = \frac{13}{28}\]

\[5)\ \frac{14^{\backslash 2}}{15} - \frac{7^{\backslash 3}}{10} = \frac{28 - 21}{30} = \frac{7}{30}\]

\[6)\ \frac{3^{\backslash 3}}{8} + \frac{1^{\backslash 4}}{6} = \frac{9 + 4}{24} = \frac{13}{24}\]

\[7)\ \frac{9^{\backslash 4}}{25} - \frac{7^{\backslash 5}}{20} = \frac{36 - 35}{100} = \frac{1}{100}\]

\[8)\ \frac{37^{\backslash 4}}{42} - \frac{17^{\backslash 7}}{24} = \frac{148 - 119}{168} =\]

\[= \frac{29}{168}\]

\[9)\ \frac{11^{\backslash 2}}{24} - \frac{3^{\backslash 3}}{16} = \frac{22 - 9}{48} = \frac{13}{48}\]

\[10)\ \frac{9^{\backslash 3}}{16} + \frac{7^{\backslash 2}}{24} - \frac{3^{\backslash 6}}{8} =\]

\[= \frac{27 + 14 - 18}{48} = \frac{23}{48}\]

\[11)\ \frac{1^{\backslash 4}}{3} - \frac{1^{\backslash 2}}{6} + \frac{1^{\backslash 3}}{4} =\]

\[= \frac{4 - 2 + 3}{12} = \frac{5}{12}\]

\[12)\ \frac{2^{\backslash 9}}{5} + \frac{4^{\backslash 3}}{15} - \frac{5^{\backslash 5}}{9} =\]

\[= \frac{18 + 12 - 25}{45} = \frac{5}{45} = \frac{1}{9}\]

\[\boxed{\mathbf{269}\mathbf{.}}\]

\[r = d\ :2\]

\[1)\ 8\ см\ :2 = 4\ см.\]

\[2)\ 5\ см\ :2 = 2,5\ см.\]

\[3)\ 9,2\ дм\ :2 = 4,6\ дм.\]