\[Схематический\ рисунок.\]
\[Дано:\]
\[ABCD - ромб;\]
\[\angle D = 8\angle CAD.\]
\[Найти:\]
\[\angle BAD.\]
\[Решение.\]
\[1)\ ABCD - ромб:\]
\[AD = CD;\ \ \ \]
\[\angle A = \angle C;\]
\[AC - биссектриса\ \angle A;\]
\[\angle BAD = 2\angle DAC.\]
\[2)\ \mathrm{\Delta}ADC - \ равнобедренный:\]
\[\angle DAC = \angle DCA;\]
\[\angle DAC + \angle ADC + \angle DCA = 180{^\circ}\]
\[\angle DAC + 8\angle DAC + \angle DAC = 180{^\circ}\]
\[10\angle DAC = 180{^\circ}\ \ \]
\[\angle DAC = 18{^\circ}.\]
\[\angle BAD = 2 \bullet 18{^\circ} = 36{^\circ}.\]
\[Ответ:\ \ 36{^\circ}.\]