\[Рисунок\ в\ учебнике.\]
\[Дано:\ \ \]
\[BK - биссектриса\ \angle CBD;\]
\[\angle ABK = 146{^\circ}.\]
\[Найти:\]
\[\angle CBD.\]
\[Решение.\]
\[1)\ \angle ABC:\]
\[\angle ABC = \angle ABK + \angle CBK\]
\[180{^\circ} = 146{^\circ} + \angle CBK\]
\[\angle CBK = 34{^\circ}.\]
\[2)\ \angle CBD:\]
\[\angle CBD = \angle DBK + \angle CBK\]
\[\angle CBD = \angle CBK + \angle CBK\]
\[\angle CBD = 2\angle CBK = 68{^\circ}.\]
\[Ответ:\ \ 68{^\circ}.\]