\[Рисунок\ в\ учебнике.\]
\[Дано:\ \ \]
\[\mathrm{\Delta}ABC = \mathrm{\Delta}A_{1}B_{1}C_{1};\]
\[\angle DBC = \angle D_{1}B_{1}C_{1}.\]
\[Доказать:\]
\[\mathrm{\Delta}DBC = \mathrm{\Delta}D_{1}B_{1}C_{1}.\]
\[Доказательство.\]
\[1)\ Так\ как\ \mathrm{\Delta}ABC = \mathrm{\Delta}A_{1}B_{1}C_{1}:\]
\[\angle BCA = \angle B_{1}C_{1}A_{1};\]
\[BC = B_{1}C_{1}.\]
\[2)\ \mathrm{\Delta}DBC = \mathrm{\Delta}D_{1}B_{1}C_{1} - по\ второму\ \]
\[признаку:\]
\[\angle BCD = \angle B_{1}C_{1}D_{1};\]
\[\angle BCA = \angle B_{1}C_{1}A_{1};\]
\[BC = B_{1}C_{1}.\]
\[Что\ и\ требовалось\ доказать.\]