\[Рисунок\ в\ учебнике.\]
\[Дано:\ \ \]
\[\angle ABD = \angle CDB;\]
\[AB = CD;\]
\[AD = 7\ см;\]
\[\angle C = 34{^\circ}.\]
\[Найти:\]
\[BC;\ \angle A.\]
\[Решение.\]
\[\mathrm{\Delta}ABD = \mathrm{\Delta}CDB - по\ первому\ \]
\[признаку:\]
\[BD - общая\ сторона;\]
\[\angle ABD = \angle CDB;\]
\[AB = CD.\]
\[Отсюда:\]
\[BC = AD = 7\ см;\]
\[\angle A = \angle C = 34{^\circ}.\]
\[Ответ:\ \ BC = 7\ см;\ \angle A = 34{^\circ}\mathbf{.}\]