\[Рисунок\ в\ учебнике.\]
\[\angle AOC = 70{^\circ};\angle MOB = 15{^\circ}.\]
\[1)\ \angle AOC\ и\ \angle COB\ смежные:\]
\[\angle AOC + \angle COB = 180{^\circ}\]
\[\angle AOC + \angle COM + \angle MOB = 180{^\circ}\]
\[70{^\circ} + \angle COM + 15{^\circ} = 180{^\circ}\]
\[\angle COM = 95{^\circ}.\]
\[2)\ \angle COM\ и\ \angle DOK\ вертикальные:\]
\[\angle DOK = \angle COM = 95{^\circ}.\]
\[3)\ \angle AOM = \angle AOC + \angle COM\]
\[\angle AOM = 70{^\circ} + 95{^\circ} = 165{^\circ}.\]
\[4)\ \angle AOK\ и\ \angle MOB\ вертикальные:\]
\[\angle AOK = \angle MOB = 15{^\circ}.\]
\[5)\ \angle AOD = \angle AOK + \angle DOK\]
\[\angle AOD = 15{^\circ} + 95{^\circ} = 110{^\circ}.\]
\[Ответ:\ \ \angle DOK = 95{^\circ};\ \]
\[\ \ \ \ \ \ \ \ \ \ \ \ \ \ \angle AOM = 165{^\circ};\ \]
\(\ \ \ \ \ \ \ \ \ \ \ \ \ \ \angle AOD = 110{^\circ}.\)