\[\boxed{\mathbf{358.}ОК\ ГДЗ\ –\ домашка\ на\ 5}\]
\[Дано:\]
\[конус.\]
\[Решение.\]
\[r = l \cdot \cos{60{^\circ}} = \frac{1}{2};\]
\[r = \frac{1}{2}.\]
\[S_{бок} = \frac{\pi l^{2}\alpha}{360{^\circ}} = \pi rl.\]
\[Градусная\ мера\ дуги\ \alpha:\]
\[\alpha = \frac{360{^\circ} \cdot \pi \cdot l \cdot l}{\pi \cdot l^{2} \cdot 2} = 180{^\circ}.\]
\[Ответ:180{^\circ}.\]