\[\boxed{\mathbf{803\ (803).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]
\[a_{12} = 30;\ \ S_{23} =\]
\[= \frac{2a_{1} + 22d}{2} \cdot 23 =\]
\[= \left( a_{1} + 11d \right) \cdot 23,\ \ а\]
\[a_{12} = a_{1} + 11d,\ \ тогда\]
\[S_{23} = a_{12} \cdot 23 = 30 \cdot 23 = 690\]
\[Ответ:690.\]