\[\boxed{\text{342\ (342).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
Пояснение.
Решение.
\[f(x) = x^{2} - 2x - 15\]
\[1)\ x^{2} - 2x - 15 = 0\]
\[x_{1}{+ x}_{2} = 2,\ \ x_{1} = 5\]
\[x_{1}x_{2} = - 15,\ \ x_{2} = - 3\]
\[Ответ:\ - 3;5.\]
\[2)\ x^{2} - 2x - 15 = - 7\]
\[x^{2} - 2x - 8 = 0\]
\[x_{1}{+ x}_{2} = 2,\ \ x_{1} = 4\]
\[x_{1}x_{2} = - 8,\ \ x_{2} = - 2\]
\[Ответ:4;\ - 2.\]
\[3)\ x^{2} - 2x - 15 = 33\]
\[x^{2} - 2x - 48 = 0\]
\[x_{1}{+ x}_{2} = 2,\ \ x_{1} = 8\]
\[x_{1}x_{2} = - 48,\ \ x_{2} = - 6\]
\[Ответ:8;\ - 6.\]