\[\boxed{\mathbf{854\ (854).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]
\[1)\frac{12n^{2} - 5n + 33}{n} =\]
\[= \frac{12n^{2}}{n} - \frac{5n}{n} + \frac{33}{n} =\]
\[= 12n - 5 + \frac{33}{n},\ \ \]
\[n = 1,\ 3,\ 11,\ 33.\]
\[2)\frac{n^{3} - 6n^{2} + 54}{n^{2}} =\]
\[= \frac{n^{3}}{n^{2}} - \frac{6n^{2}}{n^{2}} + \frac{54}{n^{2}} = n - 6 + \frac{54}{n^{2}},\ \]
\[n = \pm 1,\ 3.\ \]
\[3)\ \frac{10 - 4n}{n} = \frac{10}{n} - \frac{4n}{n} = \frac{10}{n} - 4,\]
\[n = 1,\ 2.\]
\[4)\ \frac{12 - 3n}{n} = \frac{12}{n} - \frac{3n}{n} = \frac{12}{n} - 3,\ \]
\[n = 1,\ 2,\ 3.\]