\[\boxed{\mathbf{724\ (724).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]
\[\boxed{\mathbf{72}\mathbf{4}\mathbf{\text{.\ }}Еуроки\ - \ ДЗ\ без\ мороки}\]
\[6x^{2} + 5x - \frac{1}{x + 1} = 1 - \frac{1}{x + 1}\]
\[6x^{2}\ + 5x - \frac{1}{x + 1} - 1 + \frac{1}{x + 1} = 0,\ \ \]
\[x + 1 \neq 0;\ \ x \neq - 1\]
\[6x^{2} + 5x - 1 = 0\]
\[D = 25 + 24 = 49\]
\[x = \frac{- 5 \pm 7}{12}\]
\[x_{1} = - 1\ (не\ подходит);\ \ \ x_{2} = \frac{1}{6}\]
\[Ответ:x = \frac{1}{6}.\]