Решебник по алгебре 8 класс Мерзляк Задание 713

\[\boxed{\mathbf{713\ (713).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[1)\ x_{1} = 2\]

\[x_{2} = 5\]

\[x_{1} + x_{2} = 2 + 5 = 7,\ \ b = - 7\]

\[x_{1} \cdot x_{2} = 2 \cdot 5 = 10,\ \ c = 10\]

\[Уравнение:\ x² - 7x + 10 = 0\ \]

\[2)\ x_{1} = - \frac{1}{3}\]

\[x_{2} = 2\]

\[x_{1} + x_{2} = 2 - \frac{1}{3} = \frac{5}{3},\ \ \]

\[b = - \frac{5}{3}\]

\[x_{1} \cdot x_{2} = - \frac{2}{3},\ \ c = - \frac{2}{3}\ \]

\[\ x² - \frac{5}{3}x - \frac{2}{3} = 0\ \ \ \ \ \ | \cdot 3\]

\[Уравнение:\ 3x^{2} - 5x - 2 = 0\]

\[3)\ x_{1} = - 0,2\]

\[x_{2} = - 10\]

\[x_{1} + x_{2} = - 10,2\]

\[x_{1} \cdot x_{2} = 2\ \]

\[x² + 10,2x + 2 = 0\ \ \ \ | \cdot 10\]

\[Уравнение:\ \ \]

\[10x² + 102x + 20 = 0\]

\[4)\ x_{1} = 2 - \sqrt{3}\]

\[x_{2} = 2 + \sqrt{3}\]

\[x_{1} + x_{2} = 4\]

\[x_{1} \cdot x_{2} = \ 4 - 3 = 1\]

\[{Уравнение:\ x}^{2} - 4x + 1 = 0\]

\[5)\ x_{1} = 0\]

\[x_{2} = 6\]

\[x_{1} + x_{2} = 6\]

\[x_{1} \cdot x_{2} = \ 0\]

\[Уравнение:\ \ x^{2} - 6x = 0\]

\[6)\ x_{1} = - \sqrt{7}\]

\[x_{2} = \sqrt{7}\]

\[x_{1} + x_{2} = 0\]

\[x_{1} \cdot x_{2} = - 7\ \]

\[Уравнение:\ x² - 7 = 0\]