Решебник по алгебре 8 класс Мерзляк Задание 645

\[\boxed{\mathbf{645\ (645).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]

\[3x^{2} - 2x + 4 + \ *\ = 0\]

\[Пусть\ y = \ \ *.\]

\[3x^{2} - 2x + 4 = - y\]

\[1)\ Если\ x = 0\ \ и\ \ x = 4,\ \ \ \]

\[то\ можем\ записать\ уравнение\ \]

\[так:\]

\[3x \cdot (x - 4) = 0.\]

\[Искомое\ уравнение:\]

\[3x^{2} - 2x + 4 + \ *\ = 0.\]

\[3x(x - 4) = 0\]

\[3x^{2} - 12x = 0\ \ \ \ \ \ \ \ \ и\ \text{\ \ \ \ }\]

\[3x^{2} - 2x + 4 + \ *\ = 0\ \]

\[3x^{2} - 2x - 10x + 4 - 4 = 0\]

\[\left( 3x^{2} - 2x + 4 \right)\underset{y}{\overset{- 10x - 4}{︸}} = 0\]

\[y = - 10x - 4.\]

\[2)\ Если\ x = - 1;\ \ \ x = 1,\ \ \ \]

\[запишем:\ \ \]

\[3 \cdot (x + 1)(x - 1) = 0.\]

\[Получаем:\ \ \ \]

\[3x^{2} - 3 = 0\ \ \ \ \ и\ \ \ \ \]

\[3x^{2} - 2x + 4 + \ *\ = 0.\]

\[\left( 3x^{2} - 2x + 4 \right) + \underset{y}{\overset{2x - 7}{︸}} = 0\]

\[y = 2x - 7.\]