Решебник по алгебре 7 класс Мерзляк Задание 158

\[\boxed{\text{158\ (158).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

Решение.

\[(10 \cdot 6)^{2} = 60^{2} = 3600.\]

\[10 \cdot 6^{2} = 10 \cdot 36 = 360\text{.\ }\]

\[\left( 10 \cdot ( - 6) \right)^{2} = ( - 60)^{2} = 3600.\]

\[10 \cdot ( - 6)^{2} = 10 \cdot 36 = 360.\ \]

\[\left( 10 \cdot ( - 0,4) \right)^{2} = ( - 4)^{2} = 16.\]

\[10 \cdot ( - 0,4)^{2} = 10 \cdot 0,16 = 1,6.\ \]

\[\left( 10 \cdot (0,4) \right)^{2} = (4)^{2} = 16.\]

\[10 \cdot (0,4)^{2} = 10 \cdot 0,16 = 1,6.\ \]

\[(10 \cdot 3)^{2} = (30)^{2} = 900.\]

\[10 \cdot 3^{2} = 10 \cdot 9 = 90.\ \]

\[\left( 10 \cdot (0,03) \right)^{2} = (0,3)^{2} = 0,09.\]

\[10 \cdot (0,03)^{2} = 10 \cdot 0,0009 =\]

\[= 0,009.\ \]

\[\left( 10 \cdot \left( \frac{1}{2} \right) \right)^{2} = (5)^{2} = 25.\]

\[10 \cdot \left( \frac{1}{2} \right)^{2} = 10 \cdot \frac{1}{4} = \frac{10}{4} = 2,5.\ \]

\[\left( 10 \cdot ( - 1) \right)^{2} = ( - 10)^{2} = 100.\]

\[10 \cdot ( - 1)^{2} = 10 \cdot 1 = 10.\ \]

\[(10 \cdot 0)^{2} = (0)^{2} = 0.\]

\[10 \cdot 0^{2} = 0.\ \]