Решебник по алгебре 7 класс Мерзляк ФГОС Задание 1032

 

\[\boxed{\text{1032\ (1032).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[x = 10 - y\text{\ \ }\]

\[y = 10 - x\]

\[x = \frac{7 - y}{2} = 3,5 - 0,5y\ \]

\[y = 7 - 2x\]

\[x = y + 4\ \]

\[y = - 4 + x\]

\[x = 1 + 6y\ \ \]

\[y = \frac{x - 1}{6} = \frac{1}{6}x - \frac{1}{6}\]

\[x = \frac{5y}{4} = 1\frac{1}{4}\text{y\ \ }\]

\[y = \frac{4x}{5} = 0,8x\]

\[x = \frac{- 12 - 3y}{4} = - 3 - \frac{3}{4}\text{y\ \ }\]

\[y = \frac{- 12 - 4x}{3} = - 4 - 1\frac{1}{3}x\]

\[\boxed{\text{1032.\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[1)\ y = x² - 16x\]

\[y = 0 - 0 = 0,\ \ (0;0)\]

\[x^{2} - 16x = 0\]

\[x = 0,\ \ x = 16\]

\[Ответ:(0;0);(16;0).\]

\[2)\ y = |x| - 2\]

\[y = |0| - 2 = - 2,\ \ (0;\ - 2)\]

\[|x| - 2 = 0\]

\[x = 2,\ \ x = - 2\]

\[(2;0),\ \ \ \ \ \ \ \ \ ( - 2;0)\]

\[Ответ:(2;0);( - 2;0);(0;\ - 2).\]

\[3)\ y = x³ - 9x\]

\[y = 0 - 9 \cdot 0 = 0,\ \ (0;0)\]

\[x^{3} - 9x = 0\]

\[x\left( x^{2} - 9 \right) = 0\]

\[x(x - 3)(x + 3) = 0\]

\[x = 0,\ \ x = 3,\ \ x = - 3\]

\[(0;0),\ \ \ \ \ \ \ \ \ (3;0),\ \ \ \ \ \ \ \ \ ( - 3;0)\]

\[Ответ:(0;0);(3;0);( - 3;0).\]

\[4)\ y = 0,8x\]

\[y = 0,8 \cdot 0 = 0,\ \ (0;0)\]

\[0,8x = 0,\ \ x = 0,\ \ (0;0)\]

\[Ответ:(0;0).\]