\[y = 3x^{2} + 7x + 1.\]
\[1)\ k = y^{'}(x) = 3 \bullet 2x + 7 =\]
\[= 6x + 7.\]
\[2)\ a = arctg\ k = \frac{\pi}{4};\]
\[\text{tg}\left( \text{arctg\ k} \right) = tg\frac{\pi}{4};\]
\[k = 1.\]
\[3)\ Точка\ касания:\]
\[6x + 7 = 1\]
\[6x = - 6\]
\[x = - 1;\]
\[y = 3 - 7 + 1 = - 3.\]
\[Ответ:\ \ ( - 1;\ - 3).\]