Решебник по алгебре и начала математического анализа 10 класс Колягин Задание 21

\[\boxed{\mathbf{21}.}\]

\[1)\ x\ :4\frac{1}{3} = 8\ :17\frac{1}{3}\]

\[4\frac{1}{3} \cdot 8 = 17\frac{1}{3} \cdot x\]

\[\frac{52}{3}x = \frac{13}{3} \cdot 8\]

\[\frac{52}{3}x = \frac{104}{3}\]

\[x = \frac{104}{3} \cdot \frac{3}{52}\]

\[x = 2.\]

\[2)\ 0,37\ :2\frac{5}{6} = x\ :8,5\]

\[\frac{37}{100} \cdot \frac{17}{2} = 2\frac{5}{6} \cdot x\]

\[\frac{17}{6}x = \frac{37 \cdot 17}{200}\ \]

\[x = \frac{37 \cdot 17 \cdot 6}{17 \cdot 200} = \frac{37 \cdot 3}{100} = \frac{111}{100}\]

\[x = 1,11.\]