Решебник по алгебре и начала математического анализа 10 класс Колягин Задание 20

\[\boxed{\mathbf{20}.}\]

\[1)\ \frac{3 - x^{\backslash 2}}{6} + 2^{\backslash 12} =\]

\[= \frac{2 - x^{\backslash 4}}{3} - \frac{2x + 1^{\backslash 3}}{4}\ \ \ \ \ | \cdot 12\]

\[6 - 2x + 24 = 8 - 4x - 6x - 3\]

\[- 2x + 10x = 5 - 30\]

\[8x = - 25\]

\[x = - 3\frac{1}{8}\]

\[x = - 3,125.\]

\[2)\ x^{\backslash 20} - \frac{1 - x^{\backslash 5}}{4} + \frac{2x - 3^{\backslash 2}}{10} =\]

\[= \frac{x + 3^{\backslash 4}}{5}\ \ \ \ | \cdot 20\]

\[20x - 5 + 5x + 4x - 6 =\]

\[= 4x + 12\]

\[29x - 4x = 12 + 11\]

\[25x = 23\]

\[x = \frac{23}{25} = \frac{92}{100}\]

\[x = 0,92.\]