Решебник по алгебре и начала математического анализа 10 класс Колягин Задание 136

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\[1)\ y = 2x^{2} + 5x + 3\]

\[y = 0:\]

\[2x^{2} + 5x + 3 = 0\]

\[D = 25 - 24 = 1\]

\[x_{1} = \frac{- 5 - 1}{4} = - \frac{6}{4} = - 1,5;\]

\[x_{2} = \frac{- 5 + 1}{4} = - 1.\]

\[x = 0:\]

\[y = 3.\]

\[Ответ:( - 1,5;0);( - 1;0);(0;3).\]

\[2)\ y = - 3x^{2} - x + 10\]

\[y = 0:\]

\[- 3x^{2} - x + 10 = 0\]

\[3x^{2} + x - 10 = 0\]

\[D = 1 + 120 = 121\]

\[x_{1} = \frac{- 1 + 11}{6} = \frac{10}{6} = \frac{5}{3} = 1\frac{2}{3};\]

\[x_{2} = \frac{- 1 - 11}{6} = - \frac{12}{6} = - 2.\]

\[x = 0:\]

\[y = 10.\]

\[Ответ:\left( 1\frac{2}{3};0 \right);( - 2;0);(0;10).\]