\[3,\ 7,\ 11,\ 15,\ 19,\ \ldots \Longrightarrow d = 4\]
\[a_{n} = a_{1} + (n - 1)d =\]
\[= 3 + (n - 1) \cdot 4 = 3 + 4n - 4 =\]
\[= 4n - 1 \Longrightarrow a_{n} = 4n - 1.\]