\[6 \cdot a + 4 \cdot b - 2 \cdot c\ и\ 3 \cdot a - 3 \cdot b - c\ \]
\[при\ 3 \cdot a - c = 2;b = 3:\]
\[1)\ 6a - 2c + 4b = 2 \cdot (3a - c) + 4b =\]
\[= 2 \cdot 2 + 4 \cdot 3 = 4 + 12 = 16.\]
\[2)\ 3a - c - 3b = 2 - 3 \cdot 2 = 2 - 6 = - 4.\]
\[6 \cdot a + 4 \cdot b - 2 \cdot c > 3 \cdot a - 3 \cdot b - c.\]