ВПР. Математика. 6 класс. Вариант 1. Часть 2. Вычислите: $\frac{28}{17} - \frac{5}{51} \cdot \frac{3}{4} (3 - 1\frac{1}{8})$

Решение: 1. $1\frac{1}{8} = \frac{1 \cdot 8 + 1}{8} = \frac{9}{8}$ 2. $3 - 1\frac{1}{8} = 3 - \frac{9}{8} = \frac{3 \cdot 8}{8} - \frac{9}{8} = \frac{24}{8} - \frac{9}{8} = \frac{15}{8}$ 3. $\frac{5}{51} \cdot \frac{3}{4} = \frac{5 \cdot 3}{51 \cdot 4} = \frac{15}{204} = \frac{5}{68}$ 4. $\frac{5}{68} \cdot \frac{15}{8} = \frac{5 \cdot 15}{68 \cdot 8} = \frac{75}{544}$ 5. $\frac{28}{17} - \frac{75}{544} = \frac{28 \cdot 32}{17 \cdot 32} - \frac{75}{544} = \frac{896}{544} - \frac{75}{544} = \frac{821}{544}$ Ответ: $\frac{821}{544}$