\[\frac{33^{n}}{3^{n - 4} \cdot 11^{n}} = \frac{(11 \cdot 3)^{n}}{3^{n} \cdot 3^{- 4} \cdot 11^{n}} =\]
\[= \frac{11^{n} \cdot 3^{n}}{3^{n} \cdot 11^{n} \cdot 3^{- 4}} = \frac{1}{3^{- 4}} = 3^{4} = 81\]