\[x_{1} = 2;\ \ \ x_{2} = - \frac{1}{2}:\]
\[\left( x + \frac{1}{2} \right)(x - 2) =\]
\[= x^{2} + \frac{1}{2}x - 2x - 1 =\]
\[= x^{2} - 1,5x - 1;\]
\[Преобразуем:\]
\[x^{2} - 1,5x - 1 = 0\ \ \ | \cdot 2\]
\[2x^{2} - 3x - 2 = 0.\]