Решите уравнения: (7x+1)/6-(2x-1)/3=3.

\[\frac{7x + 1}{6} - \frac{2x - 1}{3} = 3\ \ \ \ \ \ \ | \cdot 6\]

\[7x + 1 - 2 \cdot (2x - 1) = 18\]

\[7x + 1 - 4x + 2 = 18\]

\[3x = 18 - 3\]

\[3x = 15\]

\[x = 5.\]