Решите уравнение: x^2-4x-140=0.

\[x^{2} - 4x - 140 = 0\]

\[D = ( - 4)^{2} - 4 \cdot 1 \cdot ( - 140) =\]

\[= 16 + 560 = 576\]

\[\sqrt{D} = \sqrt{576} = 24\]

\[x_{1} = \frac{4 + 24}{2} = \frac{28}{2} = 14\]

\[x_{2} = \frac{4 - 24}{2} = \frac{- 20}{2} = - 10\]

\[Ответ:14;\ - 10.\]