Решите уравнение: x^2-2006x+2005=0.

\[x^{2} - 2006x + 2005 = 0\]

\[D = ( - 2006)^{2} - 4 \cdot 1 \cdot 2005 =\]

\[= 4\ 024\ 036 - 8020 =\]

\[= 4\ 016\ 016\]

\[\sqrt{D} = \sqrt{4016016} = 2004\]

\[x_{1} = \frac{2006 + 2004}{2} = \frac{4010}{2} =\]

\[= 2005\]

\[x_{2} = \frac{2006 - 2004}{2} = \frac{2}{2} = 1\]

\[Ответ:2005;1.\]