Решите уравнение: (x^2-10)/(x+2)=3x/(x+2).

\[\frac{x^{2} - 10}{x + 2} = \frac{3x}{x + 2};\ \ \ x \neq - 2\]

\[x^{2} - 10 = 3x\]

\[x^{2} - 3x - 10 = 0\]

\[x_{1} + x_{2} = 3;\ \ x_{1} \cdot x_{2} = - 10\]

\[x_{1} = - 2;\ \ \ \ x_{2} = 5.\]

\[Ответ:x = 5.\]