Решите уравнение: x^2+2x+7/(x-6)=48+7/(x-6).

\[x^{2} + 2x - 48 = 0\]

\[D = 2^{2} - 4 \cdot 1 \cdot ( - 48) =\]

\[= 4 + 192 = 196\]

\[x_{1} = \frac{- 2 + \sqrt{196}}{2 \cdot 1} = \frac{- 2 + 14}{2} =\]

\[= \frac{12}{2} = 6\ (не\ подходит)\]

\[x_{2} = \frac{- 2 - \sqrt{196}}{2 \cdot 1} = \frac{- 2 - 14}{2} =\]

\[= - \frac{16}{2} = - 8\]

\[Ответ:\ x = - 8.\]