Решите уравнение: (x+3)/x=(2x+10)/(x-3).

\[\frac{x + 3}{x} = \frac{2x + 10}{x - 3};\ \ \ x \neq 0;x \neq 3\ \ \]

\[(x + 3)(x - 3) = x(2x + 10)\]

\[x^{2} - 9 = 2x^{2} + 10x\]

\[x^{2} + 10x + 9 = 0\]

\[D_{1} = 25 - 9 = 16\]

\[x_{1} = - 5 + 4 = - 1;\]

\[x_{2} = - 5 - 4 = - 9.\]

\[Ответ:x = - 9;x = - 1.\]