Найдите область допустимых значений представленных уравнений: (x-14)/(x^2-2x-15)=(11-x^2)/(x^2+8x+15).

\[\frac{x - 14}{x^{2} - 2x - 15} = \frac{11 - x^{2}}{x^{2} + 8x + 15}\]

\[1)\ x^{2} - 2x - 15 = 0\]

\[D_{1} = 1 + 15 = 16\]

\[x_{1} = 1 + 4 = 5;\ \]

\[x_{2} = 1 - 4 = - 3.\]

\[x \neq - 3;\ \ x \neq 5.\]

\[2)\ x^{2} + 8x + 15 = 0\]

\[D_{1} = 16 - 15 = 1\]

\[x_{1} = - 4 - 1 = - 5;\]

\[x_{2} = - 4 + 1 = - 3.\]

\[x \neq - 3;\ \ x \neq - 5.\]

\[Ответ:x \neq - 3;x \neq \pm 5.\]